Python与Django的搜索与评分实践
2026/4/19 5:10:19
{}A1:=L/REF(C,1)<=0.92 AND C/REF(C,1)>=0.98;
A2:=C>MA(C,24) OR C>MA(C,60);
A3:=MA(C,5)>MA(C,24) OR MA(C,5)>MA(C,60);
XG1:A1 AND A2 AND A3;
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{}A1:=L/REF(C,1)<=0.92 AND C/REF(C,1)>=0.98;
A2:=C>MA(C,24) OR C>MA(C,60);
A3:=MA(C,5)>MA(C,24) OR MA(C,5)>MA(C,60);
XG1:A1 AND A2 AND A3;